What is the integral of (15)/(1-cos(3x)) ?

The integral of (15)/(1-cos(3x)) is -5cot((3x)/2)+C

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integral of (15)/(1-cos(3x))

\int \frac{15}{1 - cos ( 3 x )} d x

- 5 cot (\frac{3 x}{2}) + C

Solution steps

\int \frac{15}{1 - cos ( 3 x )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 15 \cdot \int \frac{1}{1 - cos ( 3 x )} d x

Apply u-substitution

: \int \frac{1}{3 ( 1 - cos ( u ) )} d u

= 15 \cdot \int \frac{1}{3 ( 1 - cos ( u ) )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 15 \cdot \frac{1}{3} \cdot \int \frac{1}{1 - cos ( u )} d u

Apply u-substitution

: \int \frac{1}{v ^{2}} d v

= 15 \cdot \frac{1}{3} \cdot \int \frac{1}{v ^{2}} d v

Apply the Power Rule

: - \frac{1}{v}

= 15 \cdot \frac{1}{3} (- \frac{1}{v})

Substitute back

= 15 \cdot \frac{1}{3} (- \frac{1}{tan ( \frac{3 x}{2} )})

Simplify

15 \cdot \frac{1}{3} (- \frac{1}{tan ( \frac{3 x}{2} )}) : - 5 cot (\frac{3 x}{2})

= - 5 cot (\frac{3 x}{2})

Add a constant to the solution

= - 5 cot (\frac{3 x}{2}) + C

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What is the integral of (15)/(1-cos(3x)) ?
The integral of (15)/(1-cos(3x)) is -5cot((3x)/2)+C