What is the integral of 1/(sec(y)) ?

The integral of 1/(sec(y)) is sin(y)+C

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integral of 1/(sec(y))

\int \frac{1}{sec ( y )} d y

sin (y) + C

Solution steps

\int \frac{1}{sec ( y )} d y

Rewrite using trig identities

= \int cos (y) d y

Use the common integral:

\int cos (y) d y = sin (y)

= sin (y)

Add a constant to the solution

= sin (y) + C

x \to 0 lim (x (sin (\frac{1}{x})))

\frac{d ^{2}}{d x ^{2}} (\frac{x}{x + 4})

\frac{\partial}{\partial x} (ln (y^{2} + x^{2}))

n = 0 \sum \infty \frac{2 n}{2 ^{n}}

\int \frac{d}{1} (e^{x^{2}} y) d x