What is the derivative of (x^2+4x/((3x^3+2)^4)) ?

The derivative of (x^2+4x/((3x^3+2)^4)) is (2(-15x^4-66x^3+2x+4))/((3x^3+2)^5)

What is the first derivative of (x^2+4x/((3x^3+2)^4)) ?

The first derivative of (x^2+4x/((3x^3+2)^4)) is (2(-15x^4-66x^3+2x+4))/((3x^3+2)^5)

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\frac{d}{d x} (\frac{x ^{2} + 4 x}{( 3 x ^{3} + 2 ) ^{4}})

\frac{2 ( - 15 x ^{4} - 66 x ^{3} + 2 x + 4 )}{( 3 x ^{3} + 2 ) ^{5}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} + 4 x}{( 3 x ^{3} + 2 ) ^{4}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} + 4 x ) ( 3 x ^{3} + 2 ) ^{4} - \frac{d}{d x} ( ( 3 x ^{3} + 2 ) ^{4} ) ( x ^{2} + 4 x )}{( ( 3 x ^{3} + 2 ) ^{4} ) ^{2}}

\frac{d}{d x} (x^{2} + 4 x) = 2 x + 4

\frac{d}{d x} ((3 x^{3} + 2)^{4}) = 36 x^{2} (3 x^{3} + 2)^{3}

= \frac{( 2 x + 4 ) ( 3 x ^{3} + 2 ) ^{4} - 36 x ^{2} ( 3 x ^{3} + 2 ) ^{3} ( x ^{2} + 4 x )}{( ( 3 x ^{3} + 2 ) ^{4} ) ^{2}}

Simplify

\frac{( 2 x + 4 ) ( 3 x ^{3} + 2 ) ^{4} - 36 x ^{2} ( 3 x ^{3} + 2 ) ^{3} ( x ^{2} + 4 x )}{( ( 3 x ^{3} + 2 ) ^{4} ) ^{2}} : \frac{2 ( - 15 x ^{4} - 66 x ^{3} + 2 x + 4 )}{( 3 x ^{3} + 2 ) ^{5}}

= \frac{2 ( - 15 x ^{4} - 66 x ^{3} + 2 x + 4 )}{( 3 x ^{3} + 2 ) ^{5}}

y^{^{'}} = (4 + 3 x)^{4}

\int (x + 9) ln (x) d x

\frac{1}{x ^{2} + 1}, 0

\frac{d}{d x} (\frac{x ^{7}}{7} + \frac{2 x}{3})

f (x) = (2 x - 5)^{4} (x^{2} + x + 1)^{5}

What is the derivative of (x^2+4x/((3x^3+2)^4)) ?
The derivative of (x^2+4x/((3x^3+2)^4)) is (2(-15x^4-66x^3+2x+4))/((3x^3+2)^5)
What is the first derivative of (x^2+4x/((3x^3+2)^4)) ?
The first derivative of (x^2+4x/((3x^3+2)^4)) is (2(-15x^4-66x^3+2x+4))/((3x^3+2)^5)