What is (\partial)/(\partial x)(2yx^2-4) ?

The answer to (\partial)/(\partial x)(2yx^2-4) is 4yx

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(\partial)/(\partial x)(2yx^2-4)

\frac{\partial}{\partial x} (2 y x^{2} - 4)

4 y x

Solution steps

\frac{\partial}{\partial x} (2 y x^{2} - 4)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y x^{2}) - \frac{\partial}{\partial x} (4)

\frac{\partial}{\partial x} (2 y x^{2}) = 4 y x

\frac{\partial}{\partial x} (4) = 0

= 4 y x - 0

Simplify

= 4 y x

\int_{2}^{\infty} \frac{1}{3 x} d x

r^{2} - 13 x^{2}

y^{^{'}} = 3 - 2 x - 0.5 y, y (0) = 1

\frac{d}{d x} ((ln (x))^{s e c (x)})

\frac{\partial}{\partial y} (x \cdot y^{2} \cdot e^{z})

What is (\partial)/(\partial x)(2yx^2-4) ?
The answer to (\partial)/(\partial x)(2yx^2-4) is 4yx