What is the derivative of F(r)= 2/(r^3) ?

The derivative of F(r)= 2/(r^3) is -6/(r^4)

What is the first derivative of F(r)= 2/(r^3) ?

The first derivative of F(r)= 2/(r^3) is -6/(r^4)

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derivative of

F (r) = \frac{2}{r ^{3}}

- \frac{6}{r ^{4}}

Solution steps

\frac{d}{d r} (\frac{2}{r ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d r} (\frac{1}{r ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d r} (r^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- 3 r^{- 3 - 1})

Simplify

2 (- 3 r^{- 3 - 1}) : - \frac{6}{r ^{4}}

= - \frac{6}{r ^{4}}

\frac{\partial}{\partial x} (\frac{6}{5} - \frac{6}{5} e^{- 20 t})

\frac{d}{d t} (2 cos (3 t))

\int_{0}^{\frac{9}{10}} \frac{1}{( 100 x ^{2} + 1 ) ^{\frac{3}{2}}} d x

{e^{3 t} sin (6 t) - t^{3} + e^{t}}

12 x^{3} - 3 y^{2} x^{4} + 1 \cdot y^{^{'}} = 0

What is the derivative of F(r)= 2/(r^3) ?
The derivative of F(r)= 2/(r^3) is -6/(r^4)
What is the first derivative of F(r)= 2/(r^3) ?
The first derivative of F(r)= 2/(r^3) is -6/(r^4)