What is the solution for 12x^3-3y^2sqrt(x^4+1)*y^'=0 ?

The solution for 12x^3-3y^2sqrt(x^4+1)*y^'=0 is y=\sqrt[3]{6sqrt(x^4+1)+c_{1}}

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12x^3-3y^2sqrt(x^4+1)*y^'=0

12 x^{3} - 3 y^{2} x^{4} + 1 \cdot y^{^{'}} = 0

y = 3 6 x^{4} + 1 + c_{1}

Solution steps

12 x^{3} - 3 y^{2} x^{4} + 1 \cdot y^{'} (x) = 0

Solve separable ODE:

y = 3 6 x^{4} + 1 + c_{1}

y = 3 6 x^{4} + 1 + c_{1}

\int \frac{1}{( x ^{2} - 49 ) ^{2}} d x

f (x) = 2 x + 2

\frac{d y}{d x} = 0.0016 y (2400 - y)

x \to 4 lim (\frac{7}{x - 4})

x \to 0 lim (3 x^{2} + 5)

What is the solution for 12x^3-3y^2sqrt(x^4+1)*y^'=0 ?
The solution for 12x^3-3y^2sqrt(x^4+1)*y^'=0 is y=\sqrt[3]{6sqrt(x^4+1)+c_{1}}