What is the tangent of f(x)=-2sin(x),\at x=-pi ?

The tangent of f(x)=-2sin(x),\at x=-pi is y=2x+2pi

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tangent of f(x)=-2sin(x),\at x=-pi

tangent of

f (x) = - 2 sin (x), at x = - π

y = 2 x + 2 π

Solution steps

Find the tangent point:

(- π, 0)

Find the slope of

f (x) = - 2 sin (x) : \frac{df ( x )}{d x} = - 2 cos (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(- π, 0) : y = 2 x + 2 π

y = 2 x + 2 π

\int_{0}^{10} x^{2} - 6 x + 5 d x

n = 1 \sum \infty \frac{1}{100 n}

\int \frac{1}{16} e^{- 4 x} d x

\frac{d}{d t} (t^{- 2})

\int e^{s} sin (t - s) d s

What is the tangent of f(x)=-2sin(x),\at x=-pi ?
The tangent of f(x)=-2sin(x),\at x=-pi is y=2x+2pi