What is (\partial)/(\partial z)(ysin(xz)) ?

The answer to (\partial)/(\partial z)(ysin(xz)) is ycos(xz)x

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(\partial)/(\partial z)(ysin(xz))

\frac{\partial}{\partial z} (y sin (x z))

y cos (x z) x

Solution steps

\frac{\partial}{\partial z} (y sin (x z))

Treat

y, x

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial z} (sin (x z))

Apply the chain rule:

cos (x z) \frac{\partial}{\partial z} (x z)

= cos (x z) \frac{\partial}{\partial z} (x z)

\frac{\partial}{\partial z} (x z) = x

= y cos (x z) x

t \to - 1 lim (\frac{t ^{10} + t ^{5} + 1}{t - 1})

1936 - 16 t^{2}

\frac{x}{x - 5}

(3.2) (5.6)

y = (x - 2) (2 x + 3)

What is (\partial)/(\partial z)(ysin(xz)) ?
The answer to (\partial)/(\partial z)(ysin(xz)) is ycos(xz)x