What is the tangent of f(x)= 3/x ,\at x=6 ?

The tangent of f(x)= 3/x ,\at x=6 is y=-1/12 x+1

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tangent of f(x)= 3/x ,\at x=6

tangent of

f (x) = \frac{3}{x}, at x = 6

y = - \frac{1}{12} x + 1

Solution steps

Find the tangent point:

(6, \frac{1}{2})

Find the slope of

f (x) = \frac{3}{x} : \frac{df ( x )}{d x} = - \frac{3}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{12}

Find the line with slope m=

- \frac{1}{12}

and passing through

(6, \frac{1}{2}) : y = - \frac{1}{12} x + 1

y = - \frac{1}{12} x + 1

\frac{d}{d x} (5 ln (cos (x)))

x \to 0 + lim (\frac{1}{6 x})

x \to 0 lim (2 (\frac{a ^{x} - 1}{x}))

\int_{1}^{12} \frac{1}{x - 10} d x

\frac{\partial}{\partial x} (\frac{e ^{x}}{x ^{2} + 10})

What is the tangent of f(x)= 3/x ,\at x=6 ?
The tangent of f(x)= 3/x ,\at x=6 is y=-1/12 x+1