What is the integral from 1 to 12 of 1/(x-10) ?

The integral from 1 to 12 of 1/(x-10) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 12 of 1/(x-10)

\int_{1}^{12} \frac{1}{x - 10} d x

diverges

Solution steps

\int_{1}^{12} \frac{1}{x - 10} d x

Find undefined (singularity) points:

x = 10

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{1}^{10} \frac{1}{x - 10} d x + \int_{10}^{12} \frac{1}{x - 10} d x

\int_{1}^{10} \frac{1}{x - 10} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\frac{\partial}{\partial x} (\frac{e ^{x}}{x ^{2} + 10})

n = 0 \sum \infty \frac{2 n + 1}{n !}

- 2 e^{x + 2} + e^{- 5}

y^{^{'}} = \frac{4 x ^{5} e ^{\frac{y}{x}} + x ^{3} y ^{2}}{x ^{4} y}

\int e^{2 x} cos (x) d x

What is the integral from 1 to 12 of 1/(x-10) ?
The integral from 1 to 12 of 1/(x-10) is diverges