What is the derivative of-2e^{x+2}+e^{-5} ?

The derivative of-2e^{x+2}+e^{-5} is -2e^{x+2}

What is the first derivative of-2e^{x+2}+e^{-5} ?

The first derivative of-2e^{x+2}+e^{-5} is -2e^{x+2}

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derivative of

- 2 e^{x + 2} + e^{- 5}

- 2 e^{x + 2}

Solution steps

\frac{d}{d x} (- 2 e^{x + 2} + e^{- 5})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 e^{x + 2}) + \frac{d}{d x} (e^{- 5})

\frac{d}{d x} (2 e^{x + 2}) = 2 e^{x + 2}

\frac{d}{d x} (e^{- 5}) = 0

= - 2 e^{x + 2} + 0

Simplify

= - 2 e^{x + 2}

y^{^{'}} = \frac{4 x ^{5} e ^{\frac{y}{x}} + x ^{3} y ^{2}}{x ^{4} y}

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\frac{d}{d x} (sin^{n} (x) cos (n) x)

\frac{d ^{2}}{d x ^{2}} (\frac{x}{1 + x ^{2}})

(x + 3) (- 2 n (6 n - 1) (- 2 x)^{n - 1})

What is the derivative of-2e^{x+2}+e^{-5} ?
The derivative of-2e^{x+2}+e^{-5} is -2e^{x+2}
What is the first derivative of-2e^{x+2}+e^{-5} ?
The first derivative of-2e^{x+2}+e^{-5} is -2e^{x+2}