What is the solution for (dy)/(dx)=2x+y,y(0)=4 ?

The solution for (dy)/(dx)=2x+y,y(0)=4 is y=-2(x+1)+6e^x

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(dy)/(dx)=2x+y,y(0)=4

\frac{d y}{d x} = 2 x + y, y (0) = 4

y = - 2 (x + 1) + 6 e^{x}

Solution steps

\frac{d y}{d x} = 2 x + y

Solve linear ODE:

y = - 2 (x + 1) + 6 e^{x}

y = - 2 (x + 1) + 6 e^{x}

\frac{d}{d x} (6 e^{- 8 x})

f (x) = 2 x + 1, (4, 3)

(x^{3} - 4 x) (2 x^{2} + 5 x)

\int e^{t (a - s)} d t

\int_{0}^{1} cos^{2} (3 π x) d x

What is the solution for (dy)/(dx)=2x+y,y(0)=4 ?
The solution for (dy)/(dx)=2x+y,y(0)=4 is y=-2(x+1)+6e^x