What is (\partial)/(\partial z)(3x^{y/z}) ?

The answer to (\partial)/(\partial z)(3x^{y/z}) is -(3yx^{y/z}ln(x))/(z^2)

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(\partial)/(\partial z)(3x^{y/z})

\frac{\partial}{\partial z} (3 x^{\frac{y}{z}})

- \frac{3 y x ^{\frac{y}{z}} ln ( x )}{z ^{2}}

Solution steps

\frac{\partial}{\partial z} (3 x^{\frac{y}{z}})

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{\partial}{\partial z} (x^{\frac{y}{z}})

Apply exponent rule:

a^{b} = e^{b l n (a)}

x^{\frac{y}{z}} = e^{\frac{y}{z} l n (x)}

= 3 \frac{\partial}{\partial z} (e^{\frac{y}{z} l n (x)})

Apply the chain rule:

e^{\frac{y}{z} l n (x)} \frac{\partial}{\partial z} (\frac{y}{z} ln (x))

= e^{\frac{y}{z} l n (x)} \frac{\partial}{\partial z} (\frac{y}{z} ln (x))

\frac{\partial}{\partial z} (\frac{y}{z} ln (x)) = - \frac{y ln ( x )}{z ^{2}}

= 3 e^{\frac{y}{z} l n (x)} (- \frac{y ln ( x )}{z ^{2}})

Simplify

3 e^{\frac{y}{z} l n (x)} (- \frac{y ln ( x )}{z ^{2}}) : - \frac{3 y x ^{\frac{y}{z}} ln ( x )}{z ^{2}}

= - \frac{3 y x ^{\frac{y}{z}} ln ( x )}{z ^{2}}

e^{x} \frac{( 2 x + 5 ) ^{2}}{x - 2}

y^{^{'}} = - 2 y + x

3 sin^{3} (x)

ln (- 3 x) + 2

\frac{\partial}{\partial x} (e^{0})

What is (\partial)/(\partial z)(3x^{y/z}) ?
The answer to (\partial)/(\partial z)(3x^{y/z}) is -(3yx^{y/z}ln(x))/(z^2)