What is taylor ln(-3x)+2 ?

The answer to taylor ln(-3x)+2 is ln(3)+2-(x+1)-1/2 (x+1)^2-1/3 (x+1)^3-1/4 (x+1)^4+\ldots

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

taylor ln(-3x)+2

taylor

ln (- 3 x) + 2

ln (3) + 2 - (x + 1) - \frac{1}{2} (x + 1)^{2} - \frac{1}{3} (x + 1)^{3} - \frac{1}{4} (x + 1)^{4} + \dots

Solution steps

Apply the Taylor Formula

= ln (3) + 2 + \frac{\frac{d}{d x} ( ln ( - 3 x ) + 2 ) ( - 1 )}{1 !} (x + 1) + \frac{\frac{d ^{2}}{d x ^{2}} ( ln ( - 3 x ) + 2 ) ( - 1 )}{2 !} (x + 1)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( ln ( - 3 x ) + 2 ) ( - 1 )}{3 !} (x + 1)^{3} + \dots

Evaluate Derivatives

= ln (3) + 2 + \frac{- 1}{1 !} (x + 1) + \frac{- 1}{2 !} (x + 1)^{2} + \frac{- 2}{3 !} (x + 1)^{3} + \frac{- 6}{4 !} (x + 1)^{4} + \dots

Refine

= ln (3) + 2 - (x + 1) - \frac{1}{2} (x + 1)^{2} - \frac{1}{3} (x + 1)^{3} - \frac{1}{4} (x + 1)^{4} + \dots

\frac{\partial}{\partial x} (e^{0})

\int \frac{7 x}{e ^{x}} d x

y = sin (x y) + π, (1, π)

f (x) = x^{4} + 3 e^{x}, at x = 0

\int 42 x (x + 7)^{5} d x

What is taylor ln(-3x)+2 ?
The answer to taylor ln(-3x)+2 is ln(3)+2-(x+1)-1/2 (x+1)^2-1/3 (x+1)^3-1/4 (x+1)^4+\ldots