What is the derivative of x^2-4x ?

The derivative of x^2-4x is 2x-4

What is the first derivative of x^2-4x ?

The first derivative of x^2-4x is 2x-4

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derivative of

x^{2} - 4 x

2 x - 4

Solution steps

\frac{d}{d x} (x^{2} - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

= 2 x - 4

\frac{d x}{d t} = 3 x t^{2}

3 sin (2 t)

\frac{d}{d x} (x^{x} sin (x))

y (1 + x^{2}) (\frac{d y}{d x}) - x (1 + y^{2}) = 0

y^{^{'}} = - \frac{csc ( y )}{sec ^{2} ( x )}