What is laplacetransform 3sin(2t) ?

The answer to laplacetransform 3sin(2t) is 6/(s^2+4)

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laplacetransform 3sin(2t)

laplace transform

3 sin (2 t)

\frac{6}{s ^{2} + 4}

Solution steps

L {3 sin (2 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 3 L {sin (2 t)}

L {sin (2 t)} : \frac{2}{s ^{2} + 4}

= 3 \cdot \frac{2}{s ^{2} + 4}

Refine

3 \frac{2}{s ^{2} + 4} : \frac{6}{s ^{2} + 4}

= \frac{6}{s ^{2} + 4}

\frac{d}{d x} (x^{x} sin (x))

y (1 + x^{2}) (\frac{d y}{d x}) - x (1 + y^{2}) = 0

y^{^{'}} = - \frac{csc ( y )}{sec ^{2} ( x )}

f (x) = (\frac{x - 2}{x + 2})^{2}, at x = - 1

\int 1 + cos (x) d x

What is laplacetransform 3sin(2t) ?
The answer to laplacetransform 3sin(2t) is 6/(s^2+4)