What is the integral from 0 to 3 of 10-x-y^2 ?

The integral from 0 to 3 of 10-x-y^2 is 30-3y^2-9/2

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integral from 0 to 3 of 10-x-y^2

\int_{0}^{3} 10 - x - y^{2} d x

30 - 3 y^{2} - \frac{9}{2}

Solution steps

\int_{0}^{3} 10 - x - y^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} 10 d x - \int_{0}^{3} y^{2} d x - \int_{0}^{3} x d x

\int_{0}^{3} 10 d x = 30

\int_{0}^{3} y^{2} d x = 3 y^{2}

\int_{0}^{3} x d x = \frac{9}{2}

= 30 - 3 y^{2} - \frac{9}{2}

f (x) = x^{2} e^{3 x}

x \to 2 + lim (2 x - 3)

\frac{d}{d x} (e^{- x} - x^{2})

\int_{0}^{0.6} 400 x d x

\int \frac{x ^{2} + x - 3}{3 x ^{3} - 2 x ^{2} + 6 x - 4} d x

What is the integral from 0 to 3 of 10-x-y^2 ?
The integral from 0 to 3 of 10-x-y^2 is 30-3y^2-9/2