What is the integral from 0 to 0.6 of 400x ?

The integral from 0 to 0.6 of 400x is 72

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integral from 0 to 0.6 of 400x

\int_{0}^{0.6} 400 x d x

72

Solution steps

\int_{0}^{0.6} 400 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 400 \cdot \int_{0}^{0.6} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.6}

= 400 [\frac{x ^{2}}{2}]_{0}^{0.6}

Simplify

= 400 [0.5 x^{2}]_{0}^{0.6}

Compute the boundaries:

0.18

= 400 \cdot 0.18

Simplify

= 72

\int \frac{x ^{2} + x - 3}{3 x ^{3} - 2 x ^{2} + 6 x - 4} d x

e^{- 5 s}

\int \frac{a ^{x}}{1 + a ^{2 x}} d x

\frac{d y}{d x} = 3 y - 5

\frac{\partial}{\partial x} (\frac{y}{2 x + 3 y})

What is the integral from 0 to 0.6 of 400x ?
The integral from 0 to 0.6 of 400x is 72