What is the integral of (cos(6x))/(sin(6x)) ?

The integral of (cos(6x))/(sin(6x)) is 1/6 ln|sin(6x)|+C

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integral of (cos(6x))/(sin(6x))

\int \frac{cos ( 6 x )}{sin ( 6 x )} d x

\frac{1}{6} ln ∣ sin (6 x) ∣ + C

Solution steps

\int \frac{cos ( 6 x )}{sin ( 6 x )} d x

Apply u-substitution

: \int \frac{1}{6 u} d u

= \int \frac{1}{6 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{6} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{6} ln ∣ u ∣

Substitute back

u = sin (6 x)

= \frac{1}{6} ln ∣ sin (6 x) ∣

Add a constant to the solution

= \frac{1}{6} ln ∣ sin (6 x) ∣ + C

\frac{\partial}{\partial x} (- 2 e^{- x^{2}} x)

\int 2 x - 6 x^{3} d x

- 5

x^{2}, 3 - 2 x

\frac{d y}{d x} = x y, y (0) = 1, y (1) = 2

What is the integral of (cos(6x))/(sin(6x)) ?
The integral of (cos(6x))/(sin(6x)) is 1/6 ln|sin(6x)|+C