What is (\partial)/(\partial x)(2x^2yz) ?

The answer to (\partial)/(\partial x)(2x^2yz) is 4xyz

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(\partial)/(\partial x)(2x^2yz)

\frac{\partial}{\partial x} (2 x^{2} yz)

4 x yz

Solution steps

\frac{\partial}{\partial x} (2 x^{2} yz)

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 yz \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 yz \cdot 2 x^{2 - 1}

Simplify

= 4 x yz

\int_{2}^{5} (4 - 2 x) d x

\frac{d}{d x} (ln (5 x^{2} + 6))

9 x^{3} - x^{2} y + y^{3} - 3

\frac{\partial}{\partial y} (x y^{2} - 2 x)

\int (x + 1)^{2} e^{1 - x} d x

What is (\partial)/(\partial x)(2x^2yz) ?
The answer to (\partial)/(\partial x)(2x^2yz) is 4xyz