What is (\partial)/(\partial y)(xy^2-2x) ?

The answer to (\partial)/(\partial y)(xy^2-2x) is 2xy

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(\partial)/(\partial y)(xy^2-2x)

\frac{\partial}{\partial y} (x y^{2} - 2 x)

2 x y

Solution steps

\frac{\partial}{\partial y} (x y^{2} - 2 x)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x y^{2}) - \frac{\partial}{\partial y} (2 x)

\frac{\partial}{\partial y} (x y^{2}) = 2 x y

\frac{\partial}{\partial y} (2 x) = 0

= 2 x y - 0

Simplify

= 2 x y

\int (x + 1)^{2} e^{1 - x} d x

f (x) = (x + 3)^{4} (7 - x)^{5}

\frac{\partial}{\partial y} (x y + z)

\frac{d}{d x} (\frac{1}{( 2 x + 3 ) ^{3}})

y = x^{2} ln (7 x)

What is (\partial)/(\partial y)(xy^2-2x) ?
The answer to (\partial)/(\partial y)(xy^2-2x) is 2xy