What is the integral of (x/((x-2)(x-3))) ?

The integral of (x/((x-2)(x-3))) is -2ln|x-2|+3ln|x-3|+C

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integral of (x/((x-2)(x-3)))

\int (\frac{x}{( x - 2 ) ( x - 3 )}) d x

- 2 ln ∣ x - 2 ∣ + 3 ln ∣ x - 3 ∣ + C

Solution steps

\int \frac{x}{( x - 2 ) ( x - 3 )} d x

Apply u-substitution

: \int \frac{u + 2}{u ( u - 1 )} d u

= \int \frac{u + 2}{u ( u - 1 )} d u

Take the partial fraction of

\frac{u + 2}{u ( u - 1 )} : - \frac{2}{u} + \frac{3}{u - 1}

= \int - \frac{2}{u} + \frac{3}{u - 1} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int \frac{2}{u} d u + \int \frac{3}{u - 1} d u

\int \frac{2}{u} d u = 2 ln ∣ u ∣

\int \frac{3}{u - 1} d u = 3 ln ∣ u - 1 ∣

= - 2 ln ∣ u ∣ + 3 ln ∣ u - 1 ∣

Substitute back

u = x - 2

= - 2 ln ∣ x - 2 ∣ + 3 ln ∣ x - 2 - 1 ∣

Simplify

= - 2 ln ∣ x - 2 ∣ + 3 ln ∣ x - 3 ∣

Add a constant to the solution

= - 2 ln ∣ x - 2 ∣ + 3 ln ∣ x - 3 ∣ + C

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What is the integral of (x/((x-2)(x-3))) ?
The integral of (x/((x-2)(x-3))) is -2ln|x-2|+3ln|x-3|+C