What is the derivative of y= 3/(x^2)-4/(x^3) ?

The derivative of y= 3/(x^2)-4/(x^3) is -6/(x^3)+(12)/(x^4)

What is the first derivative of y= 3/(x^2)-4/(x^3) ?

The first derivative of y= 3/(x^2)-4/(x^3) is -6/(x^3)+(12)/(x^4)

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derivative of

y = \frac{3}{x ^{2}} - \frac{4}{x ^{3}}

- \frac{6}{x ^{3}} + \frac{12}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{3}{x ^{2}} - \frac{4}{x ^{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{3}{x ^{2}}) - \frac{d}{d x} (\frac{4}{x ^{3}})

\frac{d}{d x} (\frac{3}{x ^{2}}) = - \frac{6}{x ^{3}}

\frac{d}{d x} (\frac{4}{x ^{3}}) = - \frac{12}{x ^{4}}

= - \frac{6}{x ^{3}} - (- \frac{12}{x ^{4}})

Simplify

= - \frac{6}{x ^{3}} + \frac{12}{x ^{4}}

\int e^{\frac{x}{60}} d x

\frac{d ^{2}}{d x ^{2}} (2 a x - x^{2})

x \to 4 lim (- (\frac{x}{x - 4}))

x^{4} a^{5} + y^{3} a + z^{6}

f (x) = e^{x} - 1

What is the derivative of y= 3/(x^2)-4/(x^3) ?
The derivative of y= 3/(x^2)-4/(x^3) is -6/(x^3)+(12)/(x^4)
What is the first derivative of y= 3/(x^2)-4/(x^3) ?
The first derivative of y= 3/(x^2)-4/(x^3) is -6/(x^3)+(12)/(x^4)