What is the derivative of f(x)=e^x-1 ?

The derivative of f(x)=e^x-1 is e^x

What is the first derivative of f(x)=e^x-1 ?

The first derivative of f(x)=e^x-1 is e^x

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derivative of

f (x) = e^{x} - 1

e^{x}

Solution steps

\frac{d}{d x} (e^{x} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) - \frac{d}{d x} (1)

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (1) = 0

= e^{x} - 0

Simplify

= e^{x}

x \to 1 lim (3 x^{3} - 5 x^{2} + x + 4)

sin (x^{2}) + \frac{1 - x}{1 + x}

\int 4 y d y

\frac{d y}{d t} = 2 y - 3 e^{- t}, y (0) = 1

y^{^{''}} + y = x cos^{3} (x)

What is the derivative of f(x)=e^x-1 ?
The derivative of f(x)=e^x-1 is e^x
What is the first derivative of f(x)=e^x-1 ?
The first derivative of f(x)=e^x-1 is e^x