What is the first derivative of x^2+5 ?

The first derivative of x^2+5 is 2x

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derivative of x^2+5

derivative of

x^{2} + 5

2 x

Solution steps

\frac{d}{d x} (x^{2} + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (5) = 0

= 2 x + 0

Simplify

= 2 x

\frac{d ^{2} y}{d t ^{2}} + 5 \frac{d y}{d t} = e^{- t}

5 y^{^{''}} + 35 y = 0

x \to 4 + lim (1)

\int \frac{1 + x}{x ^{2}} d x

\frac{d}{d x} (3 9 x + 1)