What is the limit as x approaches 3+of (x-3)/(x^2-9) ?

The limit as x approaches 3+of (x-3)/(x^2-9) is 1/6

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limit as x approaches 3+of (x-3)/(x^2-9)

x \to 3 + lim (\frac{x - 3}{x ^{2} - 9})

\frac{1}{6}

Decimal

0.16666 \dots

Solution steps

x \to 3 + lim (\frac{x - 3}{x ^{2} - 9})

Simplify

\frac{x - 3}{x ^{2} - 9} : \frac{1}{x + 3}

= x \to 3 + lim (\frac{1}{x + 3})

Plug in the value

x = 3

= \frac{1}{3 + 3}

Simplify

= \frac{1}{6}

\frac{d}{d x} (4 x^{3} - 5 x^{2} + 3 x - 5)

4 e x cos (x)

\frac{d}{d x} (arctan (2 x - 1))

x y^{^{'}} + 36 y = \frac{1}{x}

sin (x), cos (x), [0, \frac{π}{4}]

What is the limit as x approaches 3+of (x-3)/(x^2-9) ?
The limit as x approaches 3+of (x-3)/(x^2-9) is 1/6