What is area sin(x),cos(x),[0, pi/4 ] ?

The answer to area sin(x),cos(x),[0, pi/4 ] is sqrt(2)-1

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area sin(x),cos(x),[0, pi/4 ]

area

sin (x), cos (x), [0, \frac{π}{4}]

2 - 1

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{4}} ∣ sin (x) - cos (x) ∣ d x

Solve

\int_{0}^{\frac{π}{4}} ∣ sin (x) - cos (x) ∣ d x : 2 - 1

The area is:

= 2 - 1

\frac{d}{d x} ((2 x^{2} - 2)^{- 1})

\frac{d}{d x} (tan (\frac{x}{3}))

\int 5 d x

f (x) = \frac{x}{x + 1}

What is area sin(x),cos(x),[0, pi/4 ] ?
The answer to area sin(x),cos(x),[0, pi/4 ] is sqrt(2)-1