What is the integral of (\sqrt[7]{x}+\sqrt[8]{x}) ?

The integral of (\sqrt[7]{x}+\sqrt[8]{x}) is 7/8 x^{8/7}+8/9 x^{9/8}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (\sqrt[7]{x}+\sqrt[8]{x})

\frac{7}{8} x^{\frac{8}{7}} + \frac{8}{9} x^{\frac{9}{8}} + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{7}{8} x^{\frac{8}{7}} + \frac{8}{9} x^{\frac{9}{8}}

Add a constant to the solution

= \frac{7}{8} x^{\frac{8}{7}} + \frac{8}{9} x^{\frac{9}{8}} + C

4 x y^{2}

\int \frac{x}{( 1 + x ^{4} )} d x

x \to - 3 lim ((6 - 3 x) (\frac{3}{5} x - 1))

\int 2 y^{2} + y e^{x y} d x

(5 y^{2} - x y) d x + (x^{2}) d y = 0

What is the integral of (\sqrt[7]{x}+\sqrt[8]{x}) ?
The integral of (\sqrt[7]{x}+\sqrt[8]{x}) is 7/8 x^{8/7}+8/9 x^{9/8}+C