What is the limit as x approaches 0+of x*sin(1/x) ?

The limit as x approaches 0+of x*sin(1/x) is 0

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limit as x approaches 0+of x*sin(1/x)

x \to 0 + lim (x \cdot sin (\frac{1}{x}))

0

Solution steps

x \to 0 + lim (x sin (\frac{1}{x}))

Apply the Squeeze Theorem:

0

= 0

(3 sin (x))^{^{'}}

\frac{\partial}{\partial z} (e^{x y z^{8}})

f (x) = 2 sin (x), g (x) = 2 cos (x)

y^{^{''}} + 2 y^{^{'}} + y = - 4 e^{- t}

y^{^{''}} + 9 y = 4 x e^{(2 x)}, y (0) = 0, y^{^{'}} (0) = 0

What is the limit as x approaches 0+of x*sin(1/x) ?
The limit as x approaches 0+of x*sin(1/x) is 0