What is the integral from-2 to 1 of (x^3-3x+2) ?

The integral from-2 to 1 of (x^3-3x+2) is 27/4

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integral from-2 to 1 of (x^3-3x+2)

\int_{- 2}^{1} (x^{3} - 3 x + 2) d x

\frac{27}{4}

Decimal

6.75

Solution steps

\int_{- 2}^{1} x^{3} - 3 x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{1} x^{3} d x - \int_{- 2}^{1} 3 x d x + \int_{- 2}^{1} 2 d x

\int_{- 2}^{1} x^{3} d x = - \frac{15}{4}

\int_{- 2}^{1} 3 x d x = - \frac{9}{2}

\int_{- 2}^{1} 2 d x = 6

= - \frac{15}{4} - (- \frac{9}{2}) + 6

Simplify

- \frac{15}{4} - (- \frac{9}{2}) + 6 : \frac{27}{4}

= \frac{27}{4}

\frac{\partial}{\partial x} (\frac{x ^{2}}{y ^{2}})

\int_{- 1}^{2} \frac{x}{x + 2} d x

x \to 3 lim (2 x^{2} - 3 x + 4)

cot^{2} (sin (x))

\frac{d}{d x} (3 x^{3} - 5 x^{2} + 4)

What is the integral from-2 to 1 of (x^3-3x+2) ?
The integral from-2 to 1 of (x^3-3x+2) is 27/4