What is the integral from 1 to infinity of 1/(x^2+4) ?

The integral from 1 to infinity of 1/(x^2+4) is pi/4-1/2 arctan(1/2)

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integral from 1 to infinity of 1/(x^2+4)

\int_{1}^{\infty} \frac{1}{x ^{2} + 4} d x

\frac{π}{4} - \frac{1}{2} arctan (\frac{1}{2})

Decimal

0.55357 \dots

Solution steps

\int_{1}^{\infty} \frac{1}{x ^{2} + 4} d x

Compute the indefinite integral:

\int \frac{1}{x ^{2} + 4} d x = \frac{1}{2} arctan (\frac{x}{2}) + C

Compute the boundaries:

\int_{1}^{\infty} \frac{1}{x ^{2} + 4} d x = \frac{π}{4} - \frac{1}{2} arctan (\frac{1}{2})

= \frac{π}{4} - \frac{1}{2} arctan (\frac{1}{2})

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What is the integral from 1 to infinity of 1/(x^2+4) ?
The integral from 1 to infinity of 1/(x^2+4) is pi/4-1/2 arctan(1/2)