What is (\partial)/(\partial x)(3xy^2) ?

The answer to (\partial)/(\partial x)(3xy^2) is 3y^2

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(\partial)/(\partial x)(3xy^2)

\frac{\partial}{\partial x} (3 x y^{2})

3 y^{2}

Solution steps

\frac{\partial}{\partial x} (3 x y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 y^{2} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= 3 y^{2} \cdot 1

Simplify

= 3 y^{2}

\frac{d}{d x} (4 x^{3} y^{3})

\frac{d y}{d x}, y^{4} = x

\frac{\partial}{\partial x} (- 2 cos (3 x))

\int_{0}^{1} \frac{1}{1 + x} d x

n = 1 \sum \infty \frac{n}{2 n ^{4} + 2}

What is (\partial)/(\partial x)(3xy^2) ?
The answer to (\partial)/(\partial x)(3xy^2) is 3y^2