What is (\partial)/(\partial x)(-2cos(3x)) ?

The answer to (\partial)/(\partial x)(-2cos(3x)) is 6sin(3x)

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(\partial)/(\partial x)(-2cos(3x))

\frac{\partial}{\partial x} (- 2 cos (3 x))

6 sin (3 x)

Solution steps

\frac{\partial}{\partial x} (- 2 cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{\partial}{\partial x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{\partial}{\partial x} (3 x)

= - sin (3 x) \frac{\partial}{\partial x} (3 x)

\frac{\partial}{\partial x} (3 x) = 3

= - 2 (- sin (3 x) \cdot 3)

Simplify

= 6 sin (3 x)

\int_{0}^{1} \frac{1}{1 + x} d x

n = 1 \sum \infty \frac{n}{2 n ^{4} + 2}

\int_{0}^{1} e^{3 x} d x

(2, 3), (4, 5)

f (x) = 4 x + 32

What is (\partial)/(\partial x)(-2cos(3x)) ?
The answer to (\partial)/(\partial x)(-2cos(3x)) is 6sin(3x)