What is the derivative of g(x)=x^2+(7x)/2-3 ?

The derivative of g(x)=x^2+(7x)/2-3 is 2x+7/2

What is the first derivative of g(x)=x^2+(7x)/2-3 ?

The first derivative of g(x)=x^2+(7x)/2-3 is 2x+7/2

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derivative of

g (x) = x^{2} + \frac{7 x}{2} - 3

2 x + \frac{7}{2}

Solution steps

\frac{d}{d x} (x^{2} + \frac{7 x}{2} - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (\frac{7 x}{2}) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (\frac{7 x}{2}) = \frac{7}{2}

\frac{d}{d x} (3) = 0

= 2 x + \frac{7}{2} - 0

Simplify

= 2 x + \frac{7}{2}

\frac{d y}{d x} = \frac{x ^{2}}{e ^{y}}

\int_{0}^{9} x^{2} d x

x \frac{d y}{d x} - y = x

\frac{\partial}{\partial y} (y^{3} sin (4 x))

\frac{d}{d x} ((1 + 6 x^{2}) (x - x^{2}))

What is the derivative of g(x)=x^2+(7x)/2-3 ?
The derivative of g(x)=x^2+(7x)/2-3 is 2x+7/2
What is the first derivative of g(x)=x^2+(7x)/2-3 ?
The first derivative of g(x)=x^2+(7x)/2-3 is 2x+7/2