What is the limit as x approaches 0 of x/(1+e^{1/x)} ?

The limit as x approaches 0 of x/(1+e^{1/x)} is 0

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limit as x approaches 0 of x/(1+e^{1/x)}

x \to 0 lim (\frac{x}{1 + e ^{\frac{1}{x}}})

0

Solution steps

x \to 0 lim (\frac{x}{1 + e ^{\frac{1}{x}}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 0 - lim (\frac{x}{1 + e ^{\frac{1}{x}}}) = 0

x \to 0 + lim (\frac{x}{1 + e ^{\frac{1}{x}}}) = 0

= 0

\int \frac{1}{1 + 2 x} d x

x \to 0 lim (\frac{( 2 + x ) ^{2} - 4}{h ( x )})

\frac{\partial}{\partial x} (2 - x^{2} + x y - 2 y^{2})

\frac{\partial}{\partial h ( w )} (\frac{w}{h ( w ) ^{2}})

2 e^{5 x} cos (6 x)

What is the limit as x approaches 0 of x/(1+e^{1/x)} ?
The limit as x approaches 0 of x/(1+e^{1/x)} is 0