What is the derivative of f(x)=e^{-x+1}-e^{-x+1}x ?

The derivative of f(x)=e^{-x+1}-e^{-x+1}x is e^{-x+1}x-2e^{-x+1}

What is the first derivative of f(x)=e^{-x+1}-e^{-x+1}x ?

The first derivative of f(x)=e^{-x+1}-e^{-x+1}x is e^{-x+1}x-2e^{-x+1}

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derivative of

f (x) = e^{- x + 1} - e^{- x + 1} x

e^{- x + 1} x - 2 e^{- x + 1}

Solution steps

\frac{d}{d x} (e^{- x + 1} - e^{- x + 1} x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{- x + 1}) - \frac{d}{d x} (e^{- x + 1} x)

\frac{d}{d x} (e^{- x + 1}) = - e^{- x + 1}

\frac{d}{d x} (e^{- x + 1} x) = - e^{- x + 1} x + e^{- x + 1}

= - e^{- x + 1} - (- e^{- x + 1} x + e^{- x + 1})

Simplify

= e^{- x + 1} x - 2 e^{- x + 1}

\int \frac{1}{z} - \frac{x}{y ^{2}} d y

\int_{- 1}^{1} e^{x} - x^{2} - 1 d x

4 - 3 x^{3}

\int \frac{2}{x 9 x ^{2} + 1} d x

y = \frac{3}{x ^{2}} - 8 4 x

What is the derivative of f(x)=e^{-x+1}-e^{-x+1}x ?
The derivative of f(x)=e^{-x+1}-e^{-x+1}x is e^{-x+1}x-2e^{-x+1}
What is the first derivative of f(x)=e^{-x+1}-e^{-x+1}x ?
The first derivative of f(x)=e^{-x+1}-e^{-x+1}x is e^{-x+1}x-2e^{-x+1}