What is the derivative of x^3-2x^2 ?

The derivative of x^3-2x^2 is 3x^2-4x

What is the first derivative of x^3-2x^2 ?

The first derivative of x^3-2x^2 is 3x^2-4x

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\frac{d}{d x} (x^{3} - 2 x^{2})

3 x^{2} - 4 x

Solution steps

\frac{d}{d x} (x^{3} - 2 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (2 x^{2})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

= 3 x^{2} - 4 x

f (x) = 3 - \frac{18}{5 x ^{\frac{1}{10}}}

\int \frac{1}{x ^{2} - 2 x + 17} d x

\frac{3 - 2 s}{s ^{2} + 4 s + 5}

\frac{\partial}{\partial x} (ln (2 x + 2))

\frac{d}{d x} (- \frac{3}{2 ( 1 + x ) ^{\frac{3}{2}}})

What is the derivative of x^3-2x^2 ?
The derivative of x^3-2x^2 is 3x^2-4x
What is the first derivative of x^3-2x^2 ?
The first derivative of x^3-2x^2 is 3x^2-4x