What is area-x^2+10x-16,2x-4,2,8 ?

The answer to area-x^2+10x-16,2x-4,2,8 is 64/3

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area-x^2+10x-16,2x-4,2,8

area

- x^{2} + 10 x - 16, 2 x - 4, 2, 8

\frac{64}{3}

Decimal

21.33333 \dots

Solution steps

Apply the area formula:

\int_{2}^{8} - x^{2} + 10 x - 16 - (2 x - 4) d x

Solve

\int_{2}^{8} - x^{2} + 10 x - 16 - (2 x - 4) d x : \frac{64}{3}

The area is:

= \frac{64}{3}

- 5 x^{3} ln (x)

\int - e^{- x} \frac{1}{x} d x

y (x + 3) + y^{^{'}} = 0, y (- 6) = 1

\frac{d}{d x} (2 arcsin (x - 1))

\int (2 e^{5 x}) d x

What is area-x^2+10x-16,2x-4,2,8 ?
The answer to area-x^2+10x-16,2x-4,2,8 is 64/3