What is the derivative of f(x)=800-800x^{-1} ?

The derivative of f(x)=800-800x^{-1} is (800)/(x^2)

What is the first derivative of f(x)=800-800x^{-1} ?

The first derivative of f(x)=800-800x^{-1} is (800)/(x^2)

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derivative of

f (x) = 800 - 800 x^{- 1}

\frac{800}{x ^{2}}

Solution steps

\frac{d}{d x} (800 - 800 x^{- 1})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (800) - \frac{d}{d x} (800 x^{- 1})

\frac{d}{d x} (800) = 0

\frac{d}{d x} (800 x^{- 1}) = - \frac{800}{x ^{2}}

= 0 - (- \frac{800}{x ^{2}})

Simplify

= \frac{800}{x ^{2}}

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What is the derivative of f(x)=800-800x^{-1} ?
The derivative of f(x)=800-800x^{-1} is (800)/(x^2)
What is the first derivative of f(x)=800-800x^{-1} ?
The first derivative of f(x)=800-800x^{-1} is (800)/(x^2)