What is the derivative of y=(2x+5)/(sqrt(x)) ?

The derivative of y=(2x+5)/(sqrt(x)) is (2x-5)/(2xsqrt(x))

What is the first derivative of y=(2x+5)/(sqrt(x)) ?

The first derivative of y=(2x+5)/(sqrt(x)) is (2x-5)/(2xsqrt(x))

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derivative of

y = \frac{2 x + 5}{x}

\frac{2 x - 5}{2 x x}

Solution steps

\frac{d}{d x} (\frac{2 x + 5}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x + 5 ) x - \frac{d}{d x} ( x ) ( 2 x + 5 )}{( x ) ^{2}}

\frac{d}{d x} (2 x + 5) = 2

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{2 x - \frac{1}{2 x} ( 2 x + 5 )}{( x ) ^{2}}

Simplify

\frac{2 x - \frac{1}{2 x} ( 2 x + 5 )}{( x ) ^{2}} : \frac{2 x - 5}{2 x x}

= \frac{2 x - 5}{2 x x}

\int sec^{4} (x) d x

f (x) = 60 + 20 x - 4.5 x^{2}, at x = 2

- x^{2} - x + 9, - x + 7, 0

\int sin^{3} (3 x) cos^{4} (3 x) d x

\frac{\partial}{\partial x} ((1 - x) (1 - y))

What is the derivative of y=(2x+5)/(sqrt(x)) ?
The derivative of y=(2x+5)/(sqrt(x)) is (2x-5)/(2xsqrt(x))
What is the first derivative of y=(2x+5)/(sqrt(x)) ?
The first derivative of y=(2x+5)/(sqrt(x)) is (2x-5)/(2xsqrt(x))