What is (\partial)/(\partial x)((1-x)(1-y)) ?

The answer to (\partial)/(\partial x)((1-x)(1-y)) is -1+y

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(\partial)/(\partial x)((1-x)(1-y))

\frac{\partial}{\partial x} ((1 - x) (1 - y))

- 1 + y

Solution steps

\frac{\partial}{\partial x} ((1 - x) (1 - y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (1 - y) \frac{\partial}{\partial x} (1 - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (1 - y) (\frac{\partial}{\partial x} (1) - \frac{\partial}{\partial x} (x))

\frac{\partial}{\partial x} (1) = 0

\frac{\partial}{\partial x} (x) = 1

= (1 - y) (0 - 1)

Simplify

(1 - y) (0 - 1) : - 1 + y

= - 1 + y

x \to 4 + lim (\frac{x - 4}{x ^{2} - 1})

f (x) = 3 x^{6} + 9 x^{2} - 7

\frac{d}{d x} (arccos (- \frac{x}{5}))

(sin (x) - y sin (x) - 2 cos (x)) + cos (x) y^{^{'}} = 0, y (0) = - 1

\frac{d}{d x} (- 11 sin (x))

What is (\partial)/(\partial x)((1-x)(1-y)) ?
The answer to (\partial)/(\partial x)((1-x)(1-y)) is -1+y