What is the limit as x approaches 4+of (x-4)/(x^2-1) ?

The limit as x approaches 4+of (x-4)/(x^2-1) is 0

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limit as x approaches 4+of (x-4)/(x^2-1)

x \to 4 + lim (\frac{x - 4}{x ^{2} - 1})

0

Solution steps

x \to 4 + lim (\frac{x - 4}{x ^{2} - 1})

Plug in the value

x = 4

= \frac{4 - 4}{4 ^{2} - 1}

Simplify

= 0

f (x) = 3 x^{6} + 9 x^{2} - 7

\frac{d}{d x} (arccos (- \frac{x}{5}))

(sin (x) - y sin (x) - 2 cos (x)) + cos (x) y^{^{'}} = 0, y (0) = - 1

\frac{d}{d x} (- 11 sin (x))

x \to - 4 - lim (\frac{x}{x + 4})

What is the limit as x approaches 4+of (x-4)/(x^2-1) ?
The limit as x approaches 4+of (x-4)/(x^2-1) is 0