What is the solution for (sin(x)-ysin(x)-2cos(x))+cos(x)y^'=0,y(0)=-1 ?

The solution for (sin(x)-ysin(x)-2cos(x))+cos(x)y^'=0,y(0)=-1 is y=(2sin(x))/(cos(x))+1-2/(cos(x))

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(sin(x)-ysin(x)-2cos(x))+cos(x)y^'=0,y(0)=-1

(sin (x) - y sin (x) - 2 cos (x)) + cos (x) y^{^{'}} = 0, y (0) = - 1

y = \frac{2 sin ( x )}{cos ( x )} + 1 - \frac{2}{cos ( x )}

Solution steps

(sin (x) - y sin (x) - 2 cos (x)) + cos (x) y^{'} (x) = 0

Solve linear ODE:

y = \frac{2 sin ( x )}{cos ( x )} + 1 - \frac{2}{cos ( x )}

y = \frac{2 sin ( x )}{cos ( x )} + 1 - \frac{2}{cos ( x )}

\frac{d}{d x} (- 11 sin (x))

x \to - 4 - lim (\frac{x}{x + 4})

\int \frac{5}{3 + x ^{2}} d x

f (x) = x^{2} - 5 x + 5

(6, 5), (- 3, - 4)

What is the solution for (sin(x)-ysin(x)-2cos(x))+cos(x)y^'=0,y(0)=-1 ?
The solution for (sin(x)-ysin(x)-2cos(x))+cos(x)y^'=0,y(0)=-1 is y=(2sin(x))/(cos(x))+1-2/(cos(x))