What is the integral of 5/(3+x^2) ?

The integral of 5/(3+x^2) is 5/(sqrt(3))arctan(x/(sqrt(3)))+C

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integral of 5/(3+x^2)

\int \frac{5}{3 + x ^{2}} d x

\frac{5}{3} arctan (\frac{x}{3}) + C

Solution steps

\int \frac{5}{3 + x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int \frac{1}{3 + x ^{2}} d x

Apply Integral Substitution

= 5 \cdot \int \frac{1}{3 ( 1 + u ^{2} )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \frac{1}{3} \cdot \int \frac{1}{1 + u ^{2}} d u

Use the common integral:

\int \frac{1}{1 + u ^{2}} d u = arctan (u)

= 5 \cdot \frac{1}{3} arctan (u)

Substitute back

u = \frac{x}{3}

= 5 \cdot \frac{1}{3} arctan (\frac{x}{3})

Simplify

5 \cdot \frac{1}{3} arctan (\frac{x}{3}) : \frac{5}{3} arctan (\frac{x}{3})

= \frac{5}{3} arctan (\frac{x}{3})

Add a constant to the solution

= \frac{5}{3} arctan (\frac{x}{3}) + C

f (x) = x^{2} - 5 x + 5

(6, 5), (- 3, - 4)

\frac{d}{d t} (3 sin (t))

\int tan (x) d x

y = 9 + 5 x^{2} - 2 x^{3}

What is the integral of 5/(3+x^2) ?
The integral of 5/(3+x^2) is 5/(sqrt(3))arctan(x/(sqrt(3)))+C