What is the derivative of f(x)=x^3+2x^2+3x ?

The derivative of f(x)=x^3+2x^2+3x is 3x^2+4x+3

What is the first derivative of f(x)=x^3+2x^2+3x ?

The first derivative of f(x)=x^3+2x^2+3x is 3x^2+4x+3

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derivative of

f (x) = x^{3} + 2 x^{2} + 3 x

3 x^{2} + 4 x + 3

Solution steps

\frac{d}{d x} (x^{3} + 2 x^{2} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

= 3 x^{2} + 4 x + 3

\int \frac{x - 1}{x ^{2} + 2} d x

x \to 0 lim (\frac{( 7 x ^{2} - 2 x )}{x})

1 - cos (2 t)

x sin (y)

f^{^{'}} (x) = \frac{x}{8} - 1

What is the derivative of f(x)=x^3+2x^2+3x ?
The derivative of f(x)=x^3+2x^2+3x is 3x^2+4x+3
What is the first derivative of f(x)=x^3+2x^2+3x ?
The first derivative of f(x)=x^3+2x^2+3x is 3x^2+4x+3