What is the derivative of x^4+4x^2-x ?

The derivative of x^4+4x^2-x is 4x^3+8x-1

What is the first derivative of x^4+4x^2-x ?

The first derivative of x^4+4x^2-x is 4x^3+8x-1

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derivative of

x^{4} + 4 x^{2} - x

4 x^{3} + 8 x - 1

Solution steps

\frac{d}{d x} (x^{4} + 4 x^{2} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (4 x^{2}) - \frac{d x}{d x}

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d x}{d x} = 1

= 4 x^{3} + 8 x - 1

x \to - 1 lim (f (x) g (x))

\frac{\partial}{\partial x} (y^{3} e^{x y})

f (x) = 8 x

\frac{\partial}{\partial x} (\frac{8 x}{y})

4 e^{2 t}

What is the derivative of x^4+4x^2-x ?
The derivative of x^4+4x^2-x is 4x^3+8x-1
What is the first derivative of x^4+4x^2-x ?
The first derivative of x^4+4x^2-x is 4x^3+8x-1