What is the derivative of 4e^{2t} ?

The derivative of 4e^{2t} is 8e^{2t}

What is the first derivative of 4e^{2t} ?

The first derivative of 4e^{2t} is 8e^{2t}

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derivative of

4 e^{2 t}

8 e^{2 t}

Solution steps

\frac{d}{d t} (4 e^{2 t})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d t} (e^{2 t})

Apply the chain rule:

e^{2 t} \frac{d}{d t} (2 t)

= e^{2 t} \frac{d}{d t} (2 t)

\frac{d}{d t} (2 t) = 2

= 4 e^{2 t} \cdot 2

Simplify

= 8 e^{2 t}

\int (x^{4}) d x

\frac{d}{d t} (5)

\frac{d}{d x} (x^{2} + \frac{1}{2 x})

\int \frac{1}{ln ( y )} d y

\frac{d}{d x} (8 x + 1)

What is the derivative of 4e^{2t} ?
The derivative of 4e^{2t} is 8e^{2t}
What is the first derivative of 4e^{2t} ?
The first derivative of 4e^{2t} is 8e^{2t}