What is the solution for (x^3+y^3)dx+(3xy^2)dy=0 ?

The solution for (x^3+y^3)dx+(3xy^2)dy=0 is y=\sqrt[3]{-(x^3)/4+(c_{1})/x}

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(x^3+y^3)dx+(3xy^2)dy=0

(x^{3} + y^{3}) d x + (3 x y^{2}) d y = 0

Solution steps

(x^{3} + y^{3}) d x + (3 x y^{2}) d y = 0

Solve Bernoulli ODE:

y = \frac{x ^{2} - 16}{x ^{2}}

\frac{d}{d x} (\frac{x ^{2}}{7 + x})

\frac{x ^{2} + 6}{x}

\int \frac{2 x ^{3} - x ^{2} + 4 x - 4}{x ^{4} - 4 x ^{2}} d x

\int_{0}^{2} 1 0^{x} d x

What is the solution for (x^3+y^3)dx+(3xy^2)dy=0 ?
The solution for (x^3+y^3)dx+(3xy^2)dy=0 is y=\sqrt[3]{-(x^3)/4+(c_{1})/x}