What is the solution for (x(x+1)dy)/(dx)+xy=1 ?

The solution for (x(x+1)dy)/(dx)+xy=1 is y=(ln(x))/(x+1)+(c_{1})/(x+1)

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(x(x+1)dy)/(dx)+xy=1

\frac{x ( x + 1 ) d y}{d x} + x y = 1

y = \frac{ln ( x )}{x + 1} + \frac{c _{1}}{x + 1}

Solution steps

\frac{x ( x + 1 ) d y}{d x} + x y = 1

Solve linear ODE:

y = \frac{ln ( x )}{x + 1} + \frac{c _{1}}{x + 1}

y = \frac{ln ( x )}{x + 1} + \frac{c _{1}}{x + 1}

\int_{\frac{1}{2}}^{3} 14 x ln (2 x) d x

f (x) = x + \frac{2}{x}

\frac{d}{d x} (e^{2 x} - e^{- 2 x})

\frac{\partial}{\partial z} (e^{z})

y^{^{'}} = \frac{3 y ^{2} - 9}{( 2 x y )}

What is the solution for (x(x+1)dy)/(dx)+xy=1 ?
The solution for (x(x+1)dy)/(dx)+xy=1 is y=(ln(x))/(x+1)+(c_{1})/(x+1)