What is (\partial)/(\partial z)(e^z) ?

The answer to (\partial)/(\partial z)(e^z) is e^z

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(\partial)/(\partial z)(e^z)

\frac{\partial}{\partial z} (e^{z})

e^{z}

Solution steps

\frac{\partial}{\partial z} (e^{z})

Apply the common derivative:

\frac{\partial}{\partial z} (e^{z}) = e^{z}

= e^{z}

y^{^{'}} = \frac{3 y ^{2} - 9}{( 2 x y )}

\frac{\partial}{\partial x} (5 x^{6} sin (3 y^{4} z^{2}))

y^{^{''}} + 4 y^{^{'}} + 20 y = 0, y (0) = 4, y^{^{'}} (0) = - 7

\int_{- \infty}^{0} 6^{r} d r

\frac{d y}{d t} + a y = b e^{- b t}

What is (\partial)/(\partial z)(e^z) ?
The answer to (\partial)/(\partial z)(e^z) is e^z